class: center, middle, inverse, title-slide # Circle with center at the origin ## Analytic Geometry ### Arturo Sánchez González ###
arturo.sanchez@upaep.mx
### August 2021 --- class: inverse, center, middle # Again... the circle --- background-color: #FFFFFF # Geometric definition of the circle .pull-left[ </br> </br> <span style="font-size:30px">A <span style="color:green">**CIRCLE**</span> is <span style="font-size:33px">_**the set of all points in the plane** that are <span style="color:blue">a fixed distance</span> (the <span style="color:blue">radius</span>) from <span style="color:red">a fixed point</span> (the <span style="color:red">center</span>)_ ] .pull-right[ </br> <img src="circle.png" width="110%" style="display: block; margin: auto;" /> ] --- class: inverse, center, middle # How do we transform the previous definition into an equation? --- class: clear background-color: #000000 <span style="color:white;font-size:35px"> First, let's suppose that we have a **circle with center in the origin `\(O(0,0)\)` and radius** `\(r\)` </br> -- - <span style="color:white;font-size:35px"> Let's take a point `\(A(x,y)\)` in the circle. -- - <span style="color:white;font-size:35px"> Then, we know that $$ d(A,O) = r $$ -- - <span style="color:white;font-size:35px"> This implies that $$ \sqrt{(x-0)^2 + (y-0)^2} = r $$ --- class: clear background-color: #000000 - <span style="color:white;font-size:35px"> If we make the necessary reductions: $$ \sqrt{x^2 + y^2}=r $$ </br> -- - <span style="color:white;font-size:35px"> Finally, if we take squares in both sides, we get</span> <span style="font-size:35px"> $$ \color{yellow}{x^2 + y^2 = r^2} $$ -- <span style="color:white;font-size:30px">This is called the .center[ <span style="color:white;font-size:35px"><b>CANONICAL EQUATION OF A CIRCLE WITH RADIUS `\(r\)` CENTERED AT THE ORIGIN ] --- class: inverse, center, middle # Problem 1 (a) --- class: clear background-color: #000000 <span style="color:white;font-size:35px">Find the equation of a circle of radius `\(5\)` and center at the origin. --- class: inverse, center, middle # Big question: <span style="font-size:40px"> **Why is important to have an equation that represents a figure ?** --- background-color: #000000 # Main reasons to use equations </br> - <span style="font-size:30px">We have a compact representation of all the points in the plane that lie on the figure. </br> - <span style="font-size:30px">The equation allows us to confirm if a point lies on the figure just by making a substitution. --- class: inverse, center, middle # Problem 1 (b) --- class: clear background-color: #000000 <span style="color:white;font-size:35px">Does the point `\((-3, -4)\)` lie on the circle of radius `\(5\)` and center in the origin? <span style="color:white;font-size:35px"> What about the point `\((1,-5)\)`? --- class: inverse, center, middle # Problem 1 (c) --- class: clear background-color: #000000 <span style="color:white;font-size:35px">Find the equation of a circle of radius `\(\sqrt{23}\)` and center at the origin. --- class: inverse, center, middle # Problem 1 (d) --- class: clear background-color: #000000 <span style="color:white;font-size:35px">Find the elements of the circle with equation `\(x^2 + y^2 - 64 =0\)`. --- class: inverse, center, middle # Problem 2 --- class: clear background-color: #000000 <span style="color:white;font-size:35px"> Given the equation `\(x^2 + y^2 = 23\)`, determine the elements of the circle. Draw this circle. --- class: inverse, center, middle # Problem 3 --- class: clear background-color: #000000 <span style="color:white;font-size:35px"> Find the equation of the circle centered at the origin that passes through `\((5,8)\)`. --- class: inverse, center, middle # Problem 4 --- class: clear background-color: #000000 <span style="color:white;font-size:35px"> Determine the figure represented by the equation `\(6x^2+6y^2=150\)`. Make a graphical representation of this figure. --- class: inverse, center, middle # Homework --- class: clear background-color: #000000 <span style="color:white;font-size:30px"> **Problem A** <span style="color:white;font-size:35px"> Let's consider a circle with center at the origin and radius `\(13\)`. Determine its canonical equation. Draw this circle. --- class: clear background-color: #000000 <span style="color:white;font-size:30px"> **Problem B** <span style="color:white;font-size:35px"> You draw a circle that is centered at the origin. You measure the diameter of the circle to be `\(32\)` units. Does the point `\((14,8)\)` lie on the circle? Draw this circle.